
Why use - (pi/3) instead of 5pi/3 when solving sec (x)=2 for
Jun 23, 2024 · Basically, the behavior of 1+sec (x) is different in each range. You found where 1+sec (x) and y=3 intersect, but you still need to make sure the bounded region is meaningful. …
Why is the answer to this not also (5pi)/6, since inverse ... - Reddit
Feb 14, 2020 · Why is the answer to this not also (5pi)/6, since inverse operations cancel. I see that pi/6 is also true, but the instructions dont mention finding analogous point.
Why don't trig functions like arctan (1) have 2 solutions? - Reddit
Apr 25, 2020 · This is one of the tricky things about inverse functions. If you think of tangent as a function, namely y = tan (x), then there are infinitely many solutions to tan (x) = 1, namely pi/4, …
sinx是第一个被求反函数的 : r/China_irl - Reddit
sinx是第一个被求反函数的。当时sin cos tan cot接到通知来讨论三角函数的周期性问题,sinx刚到初等函数大厅,门口的守卫把sinx身边的常数拦了下来,sinx感觉到事情不太对劲,但停顿一 …
Calculator is wrong : r/learnmath - Reddit
May 17, 2020 · Calculator is wrong So my calculator (texas instruments) says that cos (3.5pi) is 3 * 10 -13 when it of course should be 0. When I use 0.5pi it works. It also works for 1.5pi and …
Can y'all help me with this? : r/trigonometry - Reddit
Nov 22, 2020 · Use the unit circle to evaluate tan (5pi/6) exactly. Solution: Tangent is the ratio of sine to cosine, tan (5pi/6) = sin (5pi/6) / cos (5pi/6). Use the unit circle to identify sine and …
Without a calculator, evaluate sin5π/6 : r/learnmath - Reddit
Jan 17, 2019 · At 5pi/6 radians, cos takes value of -sqrt (3)/2 and sin takes value of 1/2. You can think of sin as the y coordinate.
[High School Trig] Why does arcsin (1/2) = π / 6 and 5π / 6?
Mar 11, 2015 · I have the values for sin, cos, and tan memorized for the first quadrant so I understand where π / 6 comes from but from these first quadrant values but how do I obtain …
need help with arcsin (sin) problem. : r/MathHelp - Reddit
Dec 17, 2018 · need help with arcsin (sin) problem. So I have the problem arcsin (sin (5pi/3)) Since it's in quadrant four I did the formula 2pi-theta (5pi/3) and got pi/3. But it keeps saying …
Help with Calculus : r/MathHelp - Reddit
Sep 29, 2015 · Help with Calculus Consider the function F (x)=tan (1/x) a. Show that f (x) = 0 for x = 1/pi, 1/ (2pi), 1/ (3pi, ... b. Show that f (x) = 1 for x = 4/pi, 4/ (5pi), 4/ (9pi), ... c. What can you …